Answered

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The Haber process for producing ammonia commercially is represented by the equation N2(g) + 3H2(g) → 2NH3(g). If 7 L of NH3 are consumed, how many liters of H2 gas are required?

Sagot :

Step 1

The reaction:

N2(g) + 3H2(g) → 2NH3(g) (balanced and completed)

All gases are assumed to be ideal and to be at STP conditions.

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Step 2

STP conditions:

1 mole of gas = 22.4 L

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Step 3

Information provided:

7 L of NH3 produced (ammonia)

Procedure:

By stoichiometry,

1 mole H2 = 22.4 L

1 mole NH3 = 22.4 L

N2(g) + 3H2(g) → 2NH3(g)

3 x 22.4 L H2 -------- 2 x 22.4 L NH3

X -------- 7 L NH3

X = 7 L NH3 x 3 x 22.4 L H2/2 x 22.4 L NH3 = 10.5 L

Answer: 10.5 L of H2 are consumed.

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