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Suppose you chose to solve the following system of questions by multiplying the first equation by 3. Then by what number would you multiple the second equation to eliminate the x variable by adding

Suppose You Chose To Solve The Following System Of Questions By Multiplying The First Equation By 3 Then By What Number Would You Multiple The Second Equation T class=

Sagot :

Explanation: Here we are multiplying the second equation by a number and then we will add both equations and our intention is to eliminate the variable "x" of the result of the sum.

Step 1: First let's get the result of the multiplication of the first equation by 3 as follows

[tex]\begin{gathered} 4x-3x=\mleft(6\mright) \\ \mleft(4x-3x\mright)\mleft(3\mright)=\mleft(6\mright)\mleft(3\mright) \\ 12x-9x=18 \end{gathered}[/tex]

Step 2: As we can see we have a 12x on the first equation (after multiplying by 3) and a 6x on the second one so we just need to find a number that multiplies 6x that gives us -12x once 12x + (-12x) = 0x.

We can see that 6x * (-2) = -12x

So the have

[tex]\begin{gathered} 6x+y=10 \\ (6x+y)(-2)=10(-2) \\ -12x-2y=-20 \end{gathered}[/tex]

Above we have our second equation after multiplying it by -2

Step 3: Now we can try to sum both equations to see if it works as expected

see the calculation below

Final answer: As we can see above our assumption was right so the final answer is -2

View image JusufY260196
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