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Write an equation of the line that has a slope of 1/3 and passes through the point (3, 2).

Sagot :

We have to write an equation of a line with a slope of 1/3 and passes through the point (3,2).

We can write the equation in slope-point form:

[tex]y-y_0=m(x-x_0)[/tex]

In this case, m=1/3 and (x0,y0)=(3,2). Then, the equation becomes:

[tex]\begin{gathered} y-2=\frac{1}{3}(x-3) \\ y=\frac{1}{3}x-1+2 \\ y=\frac{1}{3}x+1 \end{gathered}[/tex]

Answer:

Point-slope form: y-2=(1/3)*(x-3)

Slope-intercept form: y=(1/3)*x+1

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