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3. What is the surface area of this triangular prism? 15 in. 12 in 21 in. 18 in. 2 A 846 in.

Sagot :

The surface area can be calculated below

[tex]\text{surface area=}bh+2ls+lb[/tex][tex]\begin{gathered} \text{surface area=(}18\times12\text{)}+2(21\times15)+(21\times18) \\ \text{surface area=}216+630+378 \\ \text{surface area=}1224inches^2 \end{gathered}[/tex]

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