Connect with a global community of knowledgeable individuals on IDNLearn.com. Join our knowledgeable community to find the answers you need for any topic or issue.
Sagot :
[tex]\begin{gathered} \text{POINT (2,-2)} \\ Perpendicula\text{ to the line y=}\frac{2}{5}x+2 \\ \text{FIND SLOPE-INTERCEPT EQUATION} \\ \text{Two lines are perpendicular when slope1}\cdot slope2=\text{ -1} \\ \text{slope1}\cdot slope2=\text{ -1} \\ (\frac{2}{5})\cdot slope\text{ 2=-1} \\ \text{slope 2=-1 }\cdot(\frac{5}{2}) \\ \text{slope 2 =-}\frac{5}{2} \\ y=\text{-}\frac{5}{2}x+b \\ U\sin g\text{ the point (2,-2)} \\ -2=\text{-}\frac{5}{2}\cdot(2)+b \\ -2=-5+b \\ b=-2+5 \\ b=3 \\ y=\text{-}\frac{5}{2}x+3 \\ \\ \text{The slope-intercept is }y=\text{-}\frac{5}{2}x+3 \end{gathered}[/tex]
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Thanks for visiting IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more helpful information.
