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Sagot :
Givens.
• Time = 0.64 s.
,• Tangential speed = 1.02 m/s.
The period is 0.64 seconds per revolution.
Then, we use the following formula.
[tex]v=\frac{2\pi}{T}\cdot r[/tex]Where v = 1.02 m/s and T = 0.64 seconds. Solve for r.
[tex]\begin{gathered} r=\frac{v\cdot T}{2\pi} \\ r=\frac{1.02\cdot\frac{m}{s}\cdot0.64s}{2\pi} \\ r=\frac{0.6528}{2\pi}m \\ r\approx0.104m=10.4\operatorname{cm} \end{gathered}[/tex]Therefore, the radius is 10.4 cm.
If the radius were 0.05 meters but using the same period, the tangential speed would be
[tex]\begin{gathered} v=\frac{2\pi}{T}\cdot r \\ v=\frac{2\pi}{0.64\sec}\cdot0.05m \\ v=0.50\cdot\frac{m}{s} \end{gathered}[/tex]The tangential speed would be 0.50 meters per second, which is faster than the tangential speed with a larger radius.
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