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Sagot :
Given that the distance traveled by car is
[tex]d_c=240000\text{ m}[/tex]The time taken by car is
[tex]t_c\text{ = 7200 s}[/tex]The distance traveled by the sprinter is
[tex]d_s\text{ = 100 m}[/tex]The time taken by the sprinter is
[tex]t_s\text{ = 9.5 s}[/tex]We have to find that which is traveling faster and by how much.
First, we need to calculate the individual speed of the car and the sprinter.
The speed of the car can be calculated as
[tex]\begin{gathered} v_c=\text{ }\frac{d_c}{t_c} \\ =\frac{240000}{7200} \\ =33.33\text{ m/s} \end{gathered}[/tex]The speed of the sprinter can be calculated as
[tex]\begin{gathered} v_s=\frac{d_s}{t_s} \\ =\frac{100}{9.5} \\ =10.53\text{ m/s} \end{gathered}[/tex]The speed difference between car and sprinter is
[tex]\begin{gathered} v=v_c-v_s \\ =33.33-10.53 \\ =22.8\text{ m/s} \end{gathered}[/tex]Thus, the speed of the car is greater than that of the sprinter by 22.8 m/s.
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