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The sum of three integers is 126. The second integer is twice as big as the first. Thethird integer is three times the first. Find the three integers.Use x in the equation

Sagot :

we have the following:

[tex]\begin{gathered} 126=x+2x+3x \\ \end{gathered}[/tex]

solving:

[tex]\begin{gathered} 126=6x \\ x=\frac{126}{6} \\ x=21 \end{gathered}[/tex]

therefore,

first number is 21

second number is 42 (21*2)

third number is 63 (21*3)

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