Identify the number of solutions of the system of linear equations.x+3y – z=2x + y -z=03x + 2y - 3z= -1no solutionexactly one solutioninfinitely many solutionsSolve the system using the elimination method. If there are infinitely many solutions, write the ordered triple in terms of z. If there is nosolution, leave each box empty

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TravenV208002idn TravenV208002idn

04-11-2022
Mathematics

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Identify the number of solutions of the system of linear equations.x+3y – z=2x + y -z=03x + 2y - 3z= -1no solutionexactly one solutioninfinitely many solutionsSolve the system using the elimination method. If there are infinitely many solutions, write the ordered triple in terms of z. If there is nosolution, leave each box empty

Sagot :

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TripT505147idn TripT505147idn · Answer 1 · 2022-11-04T07:25:16-04:00

The system of equations describes three planes. If they intersect at one point then they have one solution; if they do not intersect, there are no solutions; If they overlap each other, then there are infinitely many solutions.

Let us solve the system.

Let us multiply the first equation by 2 and we get

[tex]2(3x-y+2z=4)=6x-2y+4x=8[/tex]

subtracting this from the second equation gives

[tex]0=-16[/tex]

which implies no solutions. These two planes never intersect each other and it doesn't matter what the third plane does (because we want ALL THREE to intersect for a solution); therefore, this system does not have any solutions and hence we leave the blanks empty.

Sagot :

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