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Sagot :
If the estimate of the population standard deviation is 8, the sample size is 62
In this question, you want to estimate the population mean with 95% confidence with a margin of error of 2.
if the estimate of the population standard deviation is 8, we need to find the sample size.
here, α = (1 - 0.95)/2
α = 0.025
Now, we have to find z in the Ztable as such z has a pvalue of 1 - α
so, z = 1.96
Now, to find the margin of error M we have formula
M = z * σ/√n
2 = 1.96 * 8/√n
√n = 1.96 * 4
√n = 7.84
n = 61.47
n ≈ 62
Therefore, if the estimate of the population standard deviation is 8, the sample size is 62
Learn more about the sample size here:
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