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Given the reaction: C6H12O6 + 6O2 → 6CO2 + 6H2
How many molecules of C6H12O6(s ) are needed to produce 24 molecules of carbon dioxide?

Sagot :

Use the coefficients as a ratio. 1:6 = x:24. You can write these as fractions and cross multiply, 6x=24. Solve and x=4, so four molecules would be needed
Sebassandinidn

Answer:

=4moleculesC_6H_{12}O_6

Explanation:

Hello,

In this case, since 24 molecules of carbon dioxide, and considering the given reaction, the following stoichiometric calculation turns out helpful to determine the requested molecules of C₆H₁₂O₆ that are needed:

[tex]=24moleculesCO_2*\frac{1molCO_2}{6.022x10^{23}moleculesCO_2}*\frac{1molC_6H_{12}O_6}{6molCO_2}*\frac{6.022x10^{23}moleculesC_6H_{12}O_6}{1molC_6H_{12}O_6} \\=4moleculesC_6H_{12}O_6[/tex]

It is clear that Avogadro's number is needed to perform the one to six relationship between C₆H₁₂O₆ and CO₂.

Best regards.

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