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an object starts from rest and falls freely for 40 meters near the surface of planet p if the time of fall is 4 seconds what is the magnitue of the acceleration due to gravioty on planet p

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The magnitude of the acceleration due to gravity on planet p is 5 meters per seconds squared.

What is the magnitude of the acceleration due to gravity on planet p?

From the Second Equation of Motion;

s = ut + (1/2)gt²

Where v is final velocity, u is initial velocity, g is acceleration due to gravity and t is time elapsed.

Given the data in the question;

  • Initial velocity u = 0m/s
  • Height s = 40m
  • Elapsed time t = 4 s
  • Acceleration due to gravity g = ?

Plug the given data in the above formula and solve for g.

s = ut + (1/2)gt²

40m = (0 × 4s) + ( (1/2) × g × (4s)²

40m =  (1/2) × g × 16s²

Multiply both sides by 2

2 × 40m = 2 × (1/2) × g × 16s²

80m = g × 16s²

g × 16s² = 80m

g = 80m / 16s²

g = 5m/s²

Therefore, the acceleration due to gravity is 5m/s².

Learn more about Equations of Motion here: brainly.com/question/18486505

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