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1. 14.61 g of sodium chloride is dissolved in water to make 500 ml of solution. (show work) a. what is the mass/volume %? b. what is the molarity of this solution?

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14.61 g of sodium chloride is dissolved in water to make 500 ml of solution. (show work) a. what is the mass/volume %? b. what is the molarity of this solution?   0.499 (approx)

Mass of sodium chloride, m​​​​​solute=14.61 g    (given)

Volume of solution,v ​​​​​solution=500 ml=0.5 litres (given)

a. Mass/volume % is ratio of mass of solute in grams and volume of solution in ml multiplied from 100%

Mass/volume%=(m​​​​​solute/v​​​​​solution)*100%

           =(14.61/500)*100%

Mass/volume%=2.928%

b. Mass of sodium is 23 and chlorine is 35.5

Molecular mass of sodium chloride ie NaCl=23*1+35.5*1=58.5

Number of moles of NaCl is found by dividing mass of NaCl in grams by molecular mass of NaCl,

Number of moles of NaCl,n​​​​​solute=14.61/58.5

Molarity of the solution is found by dividing number of moles of solute ie sodium chloride (NaCl) from volume of solution in litres,

Thus,

Molarity of solution=n​​​​​​solute/v​​​​​​solution

        =(14.61/58.5) / 0.5

       =0.499 (approx)

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