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Solve algebraically 3^x= 243

Sagot :

3^x=243

so :

³log243=x
³log 3^5=x
x=5


or

5^√243
=3
Panoyinidn
[tex]3^{x} = 243 \\ln(3^{x}) = ln(243) \\xln(3) = ln(243) \\\frac{xln(3)}{ln(3)} = \frac{ln(243)}{ln(3)} \\x = \frac{ln(243)}{ln(3)} \\x = \frac{ln(3^{5})}{ln(3)} \\x = \frac{5ln(3)}{ln(3)} \\x = 5[/tex]
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