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let s be the set of integers from 100 through 999. some integers in s have a digit in common. for example, 256 and 530 have the digit 5 in common. how many integers from 100 through 999 must you pick in order to be sure that at least two of them have a digit in common?

Sagot :

In order to achieve at least two integers with common digits, we must choose at least 10 integers.

What is meant by an integer?

A whole number that can be positive, negative, or zero is called an integer. It is not a fraction.

All three-digit integers in the range of 100 to 999 are taken into consideration.

The ten numerals 1, 2, 3, 4, 5, 6, 7, 8, 9, 0 are all feasible.

In the worst case, there are no common digits among the nine chosen integers. It is feasible, for instance, that no two of the nine integers 111, 222, 333, 444, 555, 666, 777, 888, and 999 share any digits.

There is only one digit that was not stated in the previous nine integers, therefore if we choose a tenth three-digit integer, it must share at least one digit with the first nine integers. However, a three-digit integer cannot start with a 0, so the first digit must be something else.

One of the previous nine integers must have also used the three-digit integer. In order to achieve at least two integers with common digits, we must choose at least 10 integers.

To know more about integers, visit:

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