Experience the convenience of getting your questions answered at IDNLearn.com. Ask any question and receive timely, accurate responses from our dedicated community of experts.
Sagot :
The domain of the function y = 2 - √(-3x+2) is (-∞ , 2/3] and the range of the function is (-∞ , 2] .
In the question ,
it is given that , the function is ⇒ y = 2- √(-3x+2) .
For Domain ,
we know that the square root function is defined only when the number inside the root is non negative .
that means ,
-3x [tex]+[/tex] 2 ≥ 0
Subtracting 2 from both the sides ,
we get ,
-3x ≥ -2
x ≤ 2/3
the Domain is (-∞ , 2/3] .
For range , we know that the root function value in always non negative .
√(-3x + 2) ≥ 0
Multiply by -1 on both sides
we get ,
-√(-3x + 2) ≤ 0
Adding 2 to both the sides
2 - √(-3x + 2) ≤ 2
y ≤ 2
the range is (-∞ , 2] .
Therefore , the domain is (-∞ , 2/3] and the range is (-∞ , 2] .
How do we find the domain and range of the function y = 2- √(-3x+2) ?
Learn more about Domain and Range here
https://brainly.com/question/17107121
#SPJ4
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Thank you for choosing IDNLearn.com. We’re committed to providing accurate answers, so visit us again soon.
