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Sagot :
Six electrons are transferred in the formation of Al₂O₃.
Aluminum metal and Oxygen react to form Al₂O₃ as,
2 Al + 3/2 O₂ → Al₂O₃
Oxidation number of Al on left hand side is zero, while than on right hand side in Al₂O₃ is +3.
It means it has lost 3 electrons per one atom and six electrons per two atoms. Also, the oxidation number of O at left hand side in O₂ is zero, while that in Al₂O₃ it is -2 per atom and -6 per 3 atoms.
So, two Al atoms have lost 6 electrons and 3 O atoms have gained six electrons.
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Answer:
6
Explanation:
Al has a left-side oxidation number of zero and a right-side oxidation number of three. means that it has lost three electrons for every single atom and six for every two atoms. Additionally, the left-hand side of O2 has an oxidation number of zero, whereas Al2O3 has an oxidation number of -2 per atom and -6 per three atoms. Thus, three O atoms have received six electrons whereas two Al atoms have lost 6 electrons.
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