Get detailed and accurate answers to your questions on IDNLearn.com. Our platform offers comprehensive and accurate responses to help you make informed decisions on any topic.
Sagot :
The speed of a transverse wave on the rope is 16.359 m/s
The tension in the rope will be equal to the weight of the hanging mass:
T = mg = (1.5 kg)(9.81 m/s)
T = 14.72 N
Now, the speed of the transverse wave on the rope is given by the following formula:
V = [tex]\sqrt{T/μ}[/tex]
where,
v = speed = ?
μ = linear mass density = 0.0550kg/m
Therefore,
V = [tex]\sqrt{14.72/0.0550}[/tex]
V = 16.359 m/s
A wave that oscillates perpendicular to the direction of the wave's advance is said to be transverse. Comparatively, a longitudinal wave moves in the direction of its oscillations. Transverse waves include those in the water.
A straightforward illustration may be seen in the waves that can be made on a horizontal length of string by anchoring one end and moving the other end up and down. The waves made on a drum's membrane are another illustration. The directions in which the waves travel are parallel to the membrane plane, yet the membrane's individual points move up and down in directions that are perpendicular to that plane. Another example of a transverse wave with oscillations that are not periodic is light.
Learn more about transverse wave here:
https://brainly.com/question/13863548
#SPJ4
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is your reliable source for accurate answers. Thank you for visiting, and we hope to assist you again.
