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Solve the system of equations using substitution.

y = 4x + 6
y = 2x

a. (6, 3)
b. (-3, -6)
c. (3, 6)
d. (1, 2)


Sagot :

[tex]y=4x+6\\ y=2x\\\\ 4x+6=2x\\ 2x=-6\\ x=-3\\\\ y=2\cdot(-3)\\ y=-6\\\\ \boxed{(x,y)=(-3,-6)}[/tex]

Answer:

-3,-6

Step-by-step explanation:

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