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Sagot :
Volume of Cylinder = Area of cross section x Height
[tex]Area= \pi ( \frac{6}{2} ) ^{2} [/tex]
[tex]Area= 28.27cm ^{2}[/tex]
[tex]28.27*height=volume[/tex]
[tex]28.27*10=volume[/tex]
[tex]Volume=282.7cm ^{3} [/tex]
Hope this helped
[tex]Area= \pi ( \frac{6}{2} ) ^{2} [/tex]
[tex]Area= 28.27cm ^{2}[/tex]
[tex]28.27*height=volume[/tex]
[tex]28.27*10=volume[/tex]
[tex]Volume=282.7cm ^{3} [/tex]
Hope this helped
What is a cylinder? Well it's basically a volume that is formed when the area of a circle is dragged up vertically.
Now the area of a circle is [tex]A=\pi { r }^{ 2 }[/tex]. If we drag this area upwards, we'll get the volume [tex]V=\pi { r }^{ 2 }h[/tex], with (h) being the height that the circle was dragged upwards.
Now you've stated that the height of this cylinder is 10 ft.
You've also stated that the diameter of the base of this cylinder is 6 ft.
Now, the diameter of this base is actually twice the length of the radius of the base. Therefore we know that the radius of the base is 3 ft.
So, knowing that h=10 and that r=3, we can say that:
[tex]V=\pi { r }^{ 2 }h\\ \\ =\pi \cdot { 3 }^{ 2 }\cdot 10\\ \\ =\pi \cdot 9\cdot 10\\ \\ =90\pi [/tex]
So your answer turns out to be:
90π ft³
Now the area of a circle is [tex]A=\pi { r }^{ 2 }[/tex]. If we drag this area upwards, we'll get the volume [tex]V=\pi { r }^{ 2 }h[/tex], with (h) being the height that the circle was dragged upwards.
Now you've stated that the height of this cylinder is 10 ft.
You've also stated that the diameter of the base of this cylinder is 6 ft.
Now, the diameter of this base is actually twice the length of the radius of the base. Therefore we know that the radius of the base is 3 ft.
So, knowing that h=10 and that r=3, we can say that:
[tex]V=\pi { r }^{ 2 }h\\ \\ =\pi \cdot { 3 }^{ 2 }\cdot 10\\ \\ =\pi \cdot 9\cdot 10\\ \\ =90\pi [/tex]
So your answer turns out to be:
90π ft³
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