Regena746idn
Answered

Get the information you need with the help of IDNLearn.com's extensive Q&A platform. Whether your question is simple or complex, our community is here to provide detailed and trustworthy answers quickly and effectively.

In humans tongue rolling is dominant to the inability to tongue roll. If a heterozygous tongue roller and a non-tongue roller have a child, what are the chances the child will be a non-tongue roller? A. 0 B. 0.25 C. 0.5 D. 0.75

Sagot :

Lrathburnidn
In humans, tongue rolling is dominant to the inability to tongue roll. The chances a child will be a non-tongue roller is C. 0.5.

Answer:

The chances of a child being non - tongue roller is [tex]0.5\\[/tex]

Explanation:

Let the allele for dominant "tongue rolling trait" be represented by "T"

The allele for recessive  "non-tongue rolling trait" be represented by "t"

The genotype of a heterozygous tongue rolling parent will be "Tt"

The genotype of a homozygous non- tongue rolling parent will be "tt"

If a cross is carried out between these two individuals , the offspring  produced are as shown in the punnet square below-

T t

t Tt tt

t Tt tt

So the number of offsrpings which are non- tongue roller are two in numbers represented by "tt"

So the chances that a child will be a non-tongue roller are

[tex]\frac{2}{4} \\= 0.5\\[/tex]

Where , "4" represents the total number of offsprings produced

Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for choosing IDNLearn.com for your queries. We’re committed to providing accurate answers, so visit us again soon.