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In humans tongue rolling is dominant to the inability to tongue roll. If a heterozygous tongue roller and a non-tongue roller have a child, what are the chances the child will be a non-tongue roller? A. 0 B. 0.25 C. 0.5 D. 0.75

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Lrathburnidn
In humans, tongue rolling is dominant to the inability to tongue roll. The chances a child will be a non-tongue roller is C. 0.5.

Answer:

The chances of a child being non - tongue roller is [tex]0.5\\[/tex]

Explanation:

Let the allele for dominant "tongue rolling trait" be represented by "T"

The allele for recessive  "non-tongue rolling trait" be represented by "t"

The genotype of a heterozygous tongue rolling parent will be "Tt"

The genotype of a homozygous non- tongue rolling parent will be "tt"

If a cross is carried out between these two individuals , the offspring  produced are as shown in the punnet square below-

T t

t Tt tt

t Tt tt

So the number of offsrpings which are non- tongue roller are two in numbers represented by "tt"

So the chances that a child will be a non-tongue roller are

[tex]\frac{2}{4} \\= 0.5\\[/tex]

Where , "4" represents the total number of offsprings produced

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