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Find two condecutive odd integers such that the smaller one is twelve more than one-third the larger
Let be x and x + 2 two consecutive odd integers; You have the equation : x = 12 + ( x + 2 ) / 3 ; (3x) / 3 = 36 / 3 + ( x + 2 ) / 3 ; (3x) / 3 = ( 38 + x ) / 3 ; 3x = 38 + x ; 2x = 38 ; x = 19 ; The numbers are 19 and 21 .
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