Answered

Find answers to your most challenging questions with the help of IDNLearn.com's experts. Our experts provide timely and precise responses to help you understand and solve any issue you face.

4/x-1+6/x+1=-12/x^2-1

Sagot :

Panoyinidn
[tex]\frac{4}{x - 1} + \frac{6}{x + 1} = \frac{-12}{x^{2} - 1} [/tex]

[tex]\frac{4(x + 1)}{(x - 1)(x + 1)} + \frac{6(x - 1)}{(x - 1)(x + 1)} = \frac{-12}{x^{2} - 1} [/tex]

[tex]\frac{4x + 4}{x^{2} - 1} + \frac{6x - 6}{x^{2} - 1} = \frac{-12}{x^{2} - 1} [/tex]

[tex]\frac{10x - 2}{x^{2} - 1} = \frac{-12}{x^{2} - 1} [/tex]

[tex](10x - 2)(x^{2} - 1) = -12(x^{2} - 1)[/tex]
[tex]10x^{3} - 10x^{2} - 2x^{2} + 2 = -12(x^{2}) + 12(1)[/tex]
[tex]10x^{3} - 12x^{2} + 2 = -12x^{2} + 12[/tex]
[tex]10x^{3} - 12x^{2} + 12x^{2} + 2 = -12x^{2} + 12x^{2} + 12[/tex]
[tex]10x^{3} + 2 - 2 = 12 - 2[/tex]
[tex]\frac{10x^{3}}{10} = \frac{10}{10} [/tex]

[tex]x^{3} = 1[/tex]
[tex]x = 1[/tex]
Your participation is crucial to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. Find reliable answers at IDNLearn.com. Thanks for stopping by, and come back for more trustworthy solutions.