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Sagot :
0, 1/4, 2/4, 3/4, 1, 1 1/4, 1 2/4, 1 3/4, 2, 2 1/4, 2 2/4, 2 3/4, 3, 3 1/4, 3 2/4, 3 3/4, 4.
The skip count from 0 to 4 is [tex]0,\frac{1}{4} ,\frac{2}{4} ,\frac{3}{4} ,\frac{4}{4}=1 ,\frac{5}{4} ,\frac{6}{4} ,\frac{7}{4} \frac{8}{4}=2 ,\frac{9}{4} ,\frac{10}{4} ,\frac{11}{4} ,\frac{12}{4} = 3,\frac{13}{4},\frac{14}{4} ,\frac{15}{4} ,\frac{16}{4}=4[/tex]
What is skip counting?
Skip counting is a method of counting numbers by adding every time to the previous number.
According to the given question
We have to count by fourths from 0 to 4.
Here, we add the number [tex]\frac{1}{4}[/tex] for each counting, in such manner that the counting is represented in alternate numbers.
Therefore,
the skip count by fourth from 0 to 4 are
[tex]0,\frac{1}{4} , \frac{2}{4} ,\frac{3}{4} ,\frac{4}{4} =1,\frac{5}{4} ,\frac{6}{4} ,\frac{7}{4} ,\frac{8}{4},\frac{9}{4} ,\frac{10}{4},\frac{11}{4} ,\frac{12}{4} ,\frac{13}{4},\frac{15}{4} ,\frac{16}{4} =4[/tex]
Learn more about skip counting here:https://brainly.com/question/21555185
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