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Find the slope of the line that contains these two points.
(2, -5) and (7, -10)

Sagot :

Belcatyaidn
m=[tex] \frac{y1-y2}{x1-x2} [/tex]=[tex] \frac{-5-(-10)}{2-7} [/tex]=[tex] \frac{5}{-5} =-1[/tex]
 Answer: slope is -1
TSOidn
[tex]\sf Slope= \frac{y_2-y_1}{x_2-x_1}[/tex]

Where [tex]\sf (x_1,y_1), (x_2,y_2)[/tex] are the two points.

So

[tex]\sf Slope = \frac{ -10-(-5)}{7-2}=\frac{-10+5}{7-2}=\frac{-5}{5}=-1[/tex]

So the slope of (2,-5) and (7,-10) was [tex]\boxed{ -1}[/tex]
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