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The length of a photograph is 3cm less than twice the width. The area is 54cm². Find the dimentions of the photograph.
sub values into quadratic formula i attached picture of formula
Final answer: you will be given 2 answers 6 and -4.5. -4.5 is rejected since a negative value cannot represent length because that just doesn't make sense.
w=6
Check: L=2w-3 =2(6)-3 =12-3 =9 9*6=54
Therefore the dimensions of the photograph are 6 cm by 9 cm
A= l x w
x (2x-3)= 54
2x^2 -3x-54 =0
FACTOR
(2x+9) (x-6)= 0
use the term that will give you a positive answer, lengths cannot be negative
x-6=0
x=6 width
2(6) -3= 9 length
Hope this helps
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