Answered

IDNLearn.com is designed to help you find reliable answers to any question you have. Ask anything and receive thorough, reliable answers from our community of experienced professionals.

6x+3y=13
3x-y=4
what is the value of y

Sagot :

Nekonekoidn
There are two ways to solve this.... Elimination or substitutionSubstitution6x+3y=133x-y=4
First we free one value...
-y=4-3x
y=-4+3x

now we use this solve for x
6x+3(-4+3x)=136x-12+9x=13
15x= 13+12
x= 25/15

Now that we have x we find y
y= -4+3(25/15)y=1
Now we check
6(25/15)+3(1)=1310+3= 13
13=13
3x-y=4
3(25/15)-1=4
5-1=4 
4=4

yeah... so x= 25/15 and y= 1

now elimination (Yay... *note of sarcasm*)
6x+3y=133x-y=4 
we need to sum and both equation in a way to eliminate one variable... so we multiply 3 to eliminate y so...
6x+3y=133x-y=4 (*3)
6x+3y=139x-3y=12

now we resolve
15x= 25
x= 15/25

now we could use x in any equation to find y
6(25/15)+3y=1310+3y=13
3y=13-10
y=3/3
y=1

3x-y=4
3(25/15) -y= 4
5-y= 4
-y=4-5
-y=-1
y=1

So now we check if it is correct
6(25/15)+3(1)=1310+3= 13
13=13
3x-y=4

3(25/15)-1=4
5-1=4 
4=4
So yeah... we can now tell that x= 25/15 and y = 1
your answer is y= 1...
Hope it helped...
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your search for answers ends at IDNLearn.com. Thanks for visiting, and we look forward to helping you again soon.