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A rectangular poster has an area of 190 inches squared. The height of the poster is one inch less than twice its width. Find the dimension of the poster.
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Factoring this equation, we get (2w+19)(w-10)=0. The solutions to this equation are -9.5 and 10, but clearly the width must be positive, Substituting 10 for the width, we get 10*2-1=19 for the height.
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