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If 455-mL of 6.0 m HNO3 is used to make a 2.5 L dilution what is the molarity of the dilution?
When dilution, the molar mass of the substance will not change. The amount of HNO3 is 6.0 mol/L * 0.455L = 2.73 mol. When dilution to 2.5L, the molarity will be 2.73 mol/2.5L =1.092 mol/L.
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