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Sagot :
factors of 24 that would also add up to -10 would be -12 and 2 soo. you would factor out the n's to get:
(n-12)(n+2)
(n-12)(n+2)
Your question is : -
n² - 10n +24
we split -10 n into two numbers such that product is 24 and sum is -10n. We find the numbers be -6 and -4.
n² - 6n - 4n + 24
= n(n-6) - 4(n-6)
= (n-4)(n-6)
n² - 10n +24
we split -10 n into two numbers such that product is 24 and sum is -10n. We find the numbers be -6 and -4.
n² - 6n - 4n + 24
= n(n-6) - 4(n-6)
= (n-4)(n-6)
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