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If three trains leave a station at four o'clock, each moving in seperate directions at 37 miles per hour, and at the same time three more trains leave the same station going in the same directions but 10 miles per hour faster. How many miles will have been traveled by the six trains by five o'clock?

Sagot :

Answer:

252 miles.

Step-by-step explanation:

Take one of the first set of trains

By 5 o'clock it has travelled 1 hour, so it goes 37 miles.

Therefore the first 3 trains travel for 3*37 = 111 miles.

The other 3 travel for 3 * 47 miles during that hour.

= 3*47 = 141 miles.

Total for 6 trains = 111+ 141

= 252 miles.

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