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What is the sum of the polynomials?

[tex]\[
\left(-x^2+9\right)+\left(-3x^2-11x+4\right)
\][/tex]

A. [tex]\(-4x^2-2x+4\)[/tex]

B. [tex]\(-4x^2-11x+13\)[/tex]

C. [tex]\(2x^2+20x+4\)[/tex]

D. [tex]\(2x^2+11x+5\)[/tex]

Sagot :

GinnyAnsweridn
Let's find the sum of the polynomials [tex]\(-x^2 + 9\)[/tex] and [tex]\(-3x^2 - 11x + 4\)[/tex].

1. Combine the [tex]\(x^2\)[/tex] terms:
- The first polynomial [tex]\(-x^2 + 9\)[/tex] has a term [tex]\(-x^2\)[/tex].
- The second polynomial [tex]\(-3x^2 - 11x + 4\)[/tex] has a term [tex]\(-3x^2\)[/tex].

Adding these terms together:
[tex]\[ -x^2 + (-3x^2) = -4x^2 \][/tex]

2. Combine the [tex]\(x\)[/tex] terms:
- The first polynomial [tex]\(-x^2 + 9\)[/tex] has no [tex]\(x\)[/tex] term (which is the same as having [tex]\(0 \cdot x\)[/tex]).
- The second polynomial [tex]\(-3x^2 - 11x + 4\)[/tex] has a term [tex]\(-11x\)[/tex].

Adding these terms together:
[tex]\[ 0x + (-11x) = -11x \][/tex]

3. Combine the constant terms:
- The first polynomial [tex]\(-x^2 + 9\)[/tex] has a constant term [tex]\(9\)[/tex].
- The second polynomial [tex]\(-3x^2 - 11x + 4\)[/tex] has a constant term [tex]\(4\)[/tex].

Adding these terms together:
[tex]\[ 9 + 4 = 13 \][/tex]

So, the sum of the polynomials [tex]\(-x^2 + 9\)[/tex] and [tex]\(-3x^2 - 11x + 4\)[/tex] is:
[tex]\[ -4x^2 - 11x + 13 \][/tex]

The correct answer is:
[tex]\[ -4 x^2 - 11 x + 13 \][/tex]
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