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Sagot :
To determine the domain of the function [tex]\( f(x) = \sqrt{x+5} - 1 \)[/tex], we need to ensure that the expression inside the square root is non-negative. This is because the square root function is only defined for non-negative numbers.
Let's analyze the expression [tex]\( x + 5 \)[/tex]:
1. Non-Negativity Condition:
[tex]\[ x + 5 \geq 0 \][/tex]
2. Solving for [tex]\( x \)[/tex]:
[tex]\[ x + 5 \geq 0 \\ x \geq -5 \][/tex]
3. Interpreting the Result:
- The inequality [tex]\( x \geq -5 \)[/tex] means that [tex]\( x \)[/tex] can be any number greater than or equal to [tex]\(-5\)[/tex].
4. Domain in Interval Notation:
- The domain includes all [tex]\( x \)[/tex] values that are greater than or equal to [tex]\(-5\)[/tex].
- In interval notation, this is written as:
[tex]\[ [-5, \infty) \][/tex]
Therefore, the correct domain of the function [tex]\( f(x) = \sqrt{x+5} - 1 \)[/tex] written in interval notation is:
[tex]\[ \boxed{[-5, \infty)} \][/tex]
Let's analyze the expression [tex]\( x + 5 \)[/tex]:
1. Non-Negativity Condition:
[tex]\[ x + 5 \geq 0 \][/tex]
2. Solving for [tex]\( x \)[/tex]:
[tex]\[ x + 5 \geq 0 \\ x \geq -5 \][/tex]
3. Interpreting the Result:
- The inequality [tex]\( x \geq -5 \)[/tex] means that [tex]\( x \)[/tex] can be any number greater than or equal to [tex]\(-5\)[/tex].
4. Domain in Interval Notation:
- The domain includes all [tex]\( x \)[/tex] values that are greater than or equal to [tex]\(-5\)[/tex].
- In interval notation, this is written as:
[tex]\[ [-5, \infty) \][/tex]
Therefore, the correct domain of the function [tex]\( f(x) = \sqrt{x+5} - 1 \)[/tex] written in interval notation is:
[tex]\[ \boxed{[-5, \infty)} \][/tex]
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