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Solve for [tex]\( x \)[/tex].

[tex]\[ \frac{1}{3}|x-3| + 4 = 10 \][/tex]

A. [tex]\( x = -15 \)[/tex] and [tex]\( x = 21 \)[/tex]

B. [tex]\( x = -5 \)[/tex] and [tex]\( x = -1 \)[/tex]

C. [tex]\( x = 1 \)[/tex] and [tex]\( x = 5 \)[/tex]

D. [tex]\( x = 15 \)[/tex] and [tex]\( x = 21 \)[/tex]


Sagot :

To solve the equation [tex]\(\frac{1}{3}|x - 3| + 4 = 10\)[/tex], we need to isolate the absolute value expression and then consider the different cases it presents. Let's go through the solution step-by-step.

1. Subtract 4 from both sides to isolate the absolute value term:
[tex]\[ \frac{1}{3}|x - 3| + 4 - 4 = 10 - 4 \][/tex]
[tex]\[ \frac{1}{3}|x - 3| = 6 \][/tex]

2. Multiply both sides by 3 to eliminate the fraction:
[tex]\[ 3 \cdot \frac{1}{3}|x - 3| = 6 \cdot 3 \][/tex]
[tex]\[ |x - 3| = 18 \][/tex]

3. Consider the two cases for the absolute value expression:
[tex]\[ x - 3 = 18 \quad \text{or} \quad x - 3 = -18 \][/tex]

4. Solve each case separately:

- For [tex]\(x - 3 = 18\)[/tex]:
[tex]\[ x = 18 + 3 \][/tex]
[tex]\[ x = 21 \][/tex]

- For [tex]\(x - 3 = -18\)[/tex]:
[tex]\[ x = -18 + 3 \][/tex]
[tex]\[ x = -15 \][/tex]

Therefore, the solutions to the equation are [tex]\(x = -15\)[/tex] and [tex]\(x = 21\)[/tex].

Thus, the correct answer from the choices provided is:
- [tex]\( x = -15 \)[/tex] and [tex]\( x = 21 \)[/tex]

So, the correct choice is:
[tex]\[ \boxed{x = -15 \text{ and } x = 21} \][/tex]
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