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What is the y-coordinate of point [tex]\( D \)[/tex] after a translation of [tex]\( (x, y) \rightarrow (x+6, y-4) \)[/tex]?

[tex]\( D' (3.5, \square) \)[/tex]


Sagot :

To find the [tex]$y$[/tex]-coordinate of point [tex]$D$[/tex] after the given translation, we need to understand what translation means. A translation moves every point of a figure or a space by the same distance in a given direction.

Given translation rule: [tex]\((x, y) \rightarrow (x+6, y-4)\)[/tex].

Let's apply this rule to point [tex]\(D\)[/tex]. The starting coordinates of point [tex]\(D\)[/tex] are given as [tex]\(D'(3.5, y)\)[/tex].

1. The [tex]$x$[/tex]-coordinate of point [tex]\(D\)[/tex] is initially 3.5.
2. The [tex]$y$[/tex]-coordinate of point [tex]\(D\)[/tex] is initially unknown, let's denote it as [tex]\(y\)[/tex].

According to the translation rule [tex]\((x, y) \rightarrow (x+6, y-4)\)[/tex]:

- The new [tex]$x$[/tex]-coordinate will be [tex]\(3.5 + 6\)[/tex].
- The new [tex]$y$[/tex]-coordinate will be [tex]\(y - 4\)[/tex].

From the information given, we know that the final coordinates after the translation are:

[tex]\[ \left( 3.5 + 6, y - 4 \right) = (9.5, -4) \][/tex]

To find the new [tex]$y$[/tex]-coordinate:

[tex]\[ y - 4 = -4 \][/tex]

Solving for [tex]\(y\)[/tex]:

[tex]\[ y - 4 = -4 \\ y = -4 + 4 \\ y = 0 \][/tex]

Thus, the [tex]$y$[/tex]-coordinate of point [tex]\(D\)[/tex] before the translation was [tex]\(0\)[/tex].

Therefore, the [tex]$y$[/tex]-coordinate of point [tex]$D$[/tex] after the translation is:

[tex]\[ D^{\prime}(3.5, -4) \][/tex]

So, the [tex]$y$[/tex]-coordinate is [tex]\(-4\)[/tex].