Ores50idn
Answered

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Fill in the table below. (Take [tex]\pi = \frac{22}{7}[/tex])

\begin{tabular}{|l|l|l|l|}
\hline
Circle & Diameter & Radius & Area \\
\hline
a) & & [tex]49 \, \text{cm}[/tex] & \\
\hline
b) & [tex]7 \, \text{cm}[/tex] & & \\
\hline
c) & [tex]21 \, \text{cm}[/tex] & & \\
\hline
d) & & [tex]35 \, \text{cm}[/tex] & \\
\hline
\end{tabular}

Sagot :

GinnyAnsweridn
Let's fill in the table given the values of diameter, radius, and area for the circles.

### Circle A
- Radius: [tex]\(49 \text{ cm}\)[/tex]
- Diameter: The diameter of a circle is twice the radius. Thus, the diameter is [tex]\(2 \times 49 = 98 \text{ cm}\)[/tex].
- Area: Using the formula for the area of a circle [tex]\(A = \pi r^2\)[/tex] with [tex]\(\pi = \frac{22}{7}\)[/tex] and [tex]\(r = 49 \text{ cm}\)[/tex], the area is given as [tex]\(7546.0 \text{ cm}^2\)[/tex].

### Circle B
- Diameter: [tex]\(7 \text{ cm}\)[/tex]
- Radius: The radius is half of the diameter. Thus, the radius is [tex]\(\frac{7}{2} = 3.5 \text{ cm}\)[/tex].
- Area: Using the formula for the area of a circle [tex]\(A = \pi r^2\)[/tex] with [tex]\(\pi = \frac{22}{7}\)[/tex] and [tex]\(r = 3.5 \text{ cm}\)[/tex], the area is given as [tex]\(38.5 \text{ cm}^2\)[/tex].

### Circle C
- Diameter: [tex]\(21 \text{ cm}\)[/tex]
- Radius: The radius is half of the diameter. Thus, the radius is [tex]\(\frac{21}{2} = 10.5 \text{ cm}\)[/tex].
- Area: Using the formula for the area of a circle [tex]\(A = \pi r^2\)[/tex] with [tex]\(\pi = \frac{22}{7}\)[/tex] and [tex]\(r = 10.5 \text{ cm}\)[/tex], the area is given as [tex]\(346.5 \text{ cm}^2\)[/tex].

### Circle D
- Radius: [tex]\(35 \text{ cm}\)[/tex]
- Diameter: The diameter of a circle is twice the radius. Thus, the diameter is [tex]\(2 \times 35 = 70 \text{ cm}\)[/tex].
- Area: Using the formula for the area of a circle [tex]\(A = \pi r^2\)[/tex] with [tex]\(\pi = \frac{22}{7}\)[/tex] and [tex]\(r = 35 \text{ cm}\)[/tex], the area is given as [tex]\(3850.0 \text{ cm}^2\)[/tex].

Filling in the provided table with the calculated values:

[tex]\[ \begin{tabular}{|l|l|l|l|} \hline Circle & Diameter & Radius & Area \\ \hline વ) & $98 \text{ cm}$ & $49 \text{ cm}$ & $7546.0 \text{ cm}^2$ \\ \hline b) & $7 \text{ cm}$ & $3.5 \text{ cm}$ & $38.5 \text{ cm}^2$ \\ \hline \&) & $21 \text{ cm}$ & $10.5 \text{ cm}$ & $346.5 \text{ cm}^2$ \\ \hline ф) & $70 \text{ cm}$ & $35 \text{ cm}$ & $3850.0 \text{ cm}^2$ \\ \hline \end{tabular} \][/tex]
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