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Which inequality is true?

A. [tex]\(\frac{5}{6} \ \textless \ -\frac{1}{3}\)[/tex]

B. [tex]\(2 \frac{1}{3} \ \textgreater \ 2 \frac{1}{6}\)[/tex]

C. [tex]\(2 \ \textless \ -2 \frac{1}{2}\)[/tex]

D. [tex]\(1 \frac{1}{4} \ \textgreater \ 1 \frac{1}{3}\)[/tex]

Sagot :

GinnyAnsweridn
Let's analyze and solve each inequality step by step:

1. Inequality 1: [tex]\(\frac{5}{6} < -\frac{1}{3}\)[/tex]

To compare [tex]\(\frac{5}{6}\)[/tex] and [tex]\(-\frac{1}{3}\)[/tex], let's convert them to decimal form:
- [tex]\(\frac{5}{6} \approx 0.8333\)[/tex]
- [tex]\(-\frac{1}{3} \approx -0.3333\)[/tex]

Clearly, [tex]\(0.8333\)[/tex] is not less than [tex]\(-0.3333\)[/tex]. Therefore, [tex]\(\frac{5}{6} < -\frac{1}{3}\)[/tex] is false.

2. Inequality 2: [tex]\(2 \frac{1}{3} > 2 \frac{1}{6}\)[/tex]

Let's convert the mixed numbers to improper fractions:
- [tex]\(2 \frac{1}{3} = 2 + \frac{1}{3} = \frac{6}{3} + \frac{1}{3} = \frac{7}{3}\)[/tex]
- [tex]\(2 \frac{1}{6} = 2 + \frac{1}{6} = \frac{12}{6} + \frac{1}{6} = \frac{13}{6}\)[/tex]

We need to compare [tex]\(\frac{7}{3}\)[/tex] and [tex]\(\frac{13}{6}\)[/tex]:
- [tex]\(\frac{7}{3}\)[/tex] can be written as [tex]\(\frac{14}{6}\)[/tex]

Clearly, [tex]\(\frac{14}{6} > \frac{13}{6}\)[/tex]. Therefore, [tex]\(2 \frac{1}{3} > 2 \frac{1}{6}\)[/tex] is true.

3. Inequality 3: [tex]\(2 < -2 \frac{1}{2}\)[/tex]

Let's convert the mixed number to an improper fraction:
- [tex]\(-2 \frac{1}{2} = -2 - \frac{1}{2} = -2.5\)[/tex]

Clearly, [tex]\(2\)[/tex] is not less than [tex]\(-2.5\)[/tex]. Therefore, [tex]\(2 < -2 \frac{1}{2}\)[/tex] is false.

4. Inequality 4: [tex]\(1 \frac{1}{4} > 1 \frac{1}{3}\)[/tex]

Let's convert the mixed numbers to improper fractions:
- [tex]\(1 \frac{1}{4} = 1 + \frac{1}{4} = \frac{4}{4} + \frac{1}{4} = \frac{5}{4}\)[/tex]
- [tex]\(1 \frac{1}{3} = 1 + \frac{1}{3} = \frac{3}{3} + \frac{1}{3} = \frac{4}{3}\)[/tex]

We need to compare [tex]\(\frac{5}{4}\)[/tex] and [tex]\(\frac{4}{3}\)[/tex]:
- Converting [tex]\(\frac{5}{4}\)[/tex] and [tex]\(\frac{4}{3}\)[/tex] to decimal form:
- [tex]\(\frac{5}{4} = 1.25\)[/tex]
- [tex]\(\frac{4}{3} \approx 1.3333\)[/tex]

Clearly, [tex]\(1.25\)[/tex] is not greater than [tex]\(1.3333\)[/tex]. Therefore, [tex]\(1 \frac{1}{4} > 1 \frac{1}{3}\)[/tex] is false.

So, the only true inequality is:

[tex]\[ 2 \frac{1}{3} > 2 \frac{1}{6} \][/tex]

This corresponds to Inequality 2.
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