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Question 10 of 10

What is the first quantum number of the [tex]2s^2[/tex] electron in phosphorus [tex]1s^2 2s^2 2p^6 3s^2 3p^3[/tex]?

A. [tex]n=0[/tex]
B. [tex]n=1[/tex]
C. [tex]n=2[/tex]
D. [tex]n=3[/tex]


Sagot :

To determine the first quantum number (often referred to as the principal quantum number, [tex]\( n \)[/tex]) of the [tex]\( 2s^2 \)[/tex] electrons in the electron configuration of phosphorus ([tex]\( \mathrm{P} \)[/tex]), let's carefully examine the given electron configuration.

The electron configuration for phosphorus ([tex]\( \mathrm{P} \)[/tex]) is:

[tex]\[ 1s^2 2s^2 2p^6 3s^2 3p^3 \][/tex]

In this electron configuration:

- The term [tex]\( 1s^2 \)[/tex] tells us there are 2 electrons in the first energy level (principal quantum number [tex]\( n = 1 \)[/tex]) in an [tex]\( s \)[/tex] orbital.
- The term [tex]\( 2s^2 \)[/tex] tells us there are 2 electrons in the second energy level (principal quantum number [tex]\( n = 2 \)[/tex]) in an [tex]\( s \)[/tex] orbital.
- The term [tex]\( 2p^6 \)[/tex] tells us there are 6 electrons in the second energy level (principal quantum number [tex]\( n = 2 \)[/tex]) in a [tex]\( p \)[/tex] orbital.
- The term [tex]\( 3s^2 \)[/tex] tells us there are 2 electrons in the third energy level (principal quantum number [tex]\( n = 3 \)[/tex]) in an [tex]\( s \)[/tex] orbital.
- The term [tex]\( 3p^3 \)[/tex] tells us there are 3 electrons in the third energy level (principal quantum number [tex]\( n = 3 \)[/tex]) in a [tex]\( p \)[/tex] orbital.

The question specifically asks for the first quantum number of the [tex]\( 2s^2 \)[/tex] electrons. Here, the [tex]\( 2s^2 \)[/tex] notation indicates that these electrons reside in the second energy level, which corresponds to the principal quantum number [tex]\( n = 2 \)[/tex].

Hence, the correct answer is:
C. [tex]\( n = 2 \)[/tex]
I think the answer is C