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Evaluate the expression [tex]$\frac{x^3+y^3}{x^2-y^2}$[/tex], given [tex]$x=4$[/tex] and [tex]$y=2$[/tex].

Sagot :

Claro, resolveremos la expresión [tex]\(\frac{x^3 + y^3}{x^2 - y^2}\)[/tex] cuando [tex]\(x = 4\)[/tex] y [tex]\(y = 2\)[/tex] paso a paso.

1. Calcular el numerador [tex]\(x^3 + y^3\)[/tex]:
[tex]\[ x^3 = 4^3 = 64 \][/tex]
[tex]\[ y^3 = 2^3 = 8 \][/tex]
Sumamos estos valores:
[tex]\[ x^3 + y^3 = 64 + 8 = 72 \][/tex]

2. Calcular el denominador [tex]\(x^2 - y^2\)[/tex]:
[tex]\[ x^2 = 4^2 = 16 \][/tex]
[tex]\[ y^2 = 2^2 = 4 \][/tex]
Restamos estos valores:
[tex]\[ x^2 - y^2 = 16 - 4 = 12 \][/tex]

3. Dividir el numerador entre el denominador:
[tex]\[ \frac{x^3 + y^3}{x^2 - y^2} = \frac{72}{12} = 6 \][/tex]

Entonces, el resultado de la expresión [tex]\(\frac{x^3 + y^3}{x^2 - y^2}\)[/tex] cuando [tex]\(x = 4\)[/tex] y [tex]\(y = 2\)[/tex] es [tex]\(\boxed{6}\)[/tex].