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This formula equation is unbalanced.
[tex]\ \textless \ br/\ \textgreater \ BaCl_2(aq) + Na_2CO_3(aq) \rightarrow BaCO_3(s) + NaCl(aq)\ \textless \ br/\ \textgreater \ [/tex]

Which coefficient should be placed in front of [tex]NaCl[/tex] to balance this equation?
1. 1
2. 2
3. 3
4. 4

Sagot :

GinnyAnsweridn
To balance the given chemical equation:

[tex]\[ \text{BaCl}_2(\text{aq}) + \text{Na}_2\text{CO}_3(\text{aq}) \rightarrow \text{BaCO}_3(\text{s}) + \text{NaCl}(\text{aq}) \][/tex]

we need to ensure that the number of each type of atom on both sides of the equation is equal.

1. Count the atoms on the left side of the equation:
- [tex]\( \text{Ba} \)[/tex]: 1
- [tex]\( \text{Cl} \)[/tex]: 2
- [tex]\( \text{Na} \)[/tex]: 2
- [tex]\( \text{C} \)[/tex]: 1
- [tex]\( \text{O} \)[/tex]: 3

2. Count the atoms on the right side of the equation:
- [tex]\( \text{Ba} \)[/tex]: 1
- [tex]\( \text{Cl} \)[/tex]: 1
- [tex]\( \text{Na} \)[/tex]: 1
- [tex]\( \text{C} \)[/tex]: 1
- [tex]\( \text{O} \)[/tex]: 3

From this initial count, it is clear that the chlorine ([tex]\( \text{Cl} \)[/tex]) and sodium ([tex]\( \text{Na} \)[/tex]) atoms are not balanced.

3. Balance the chlorine (Cl) and sodium (Na) atoms:
- On the left side, we have 2 chlorine atoms and 2 sodium atoms.
- On the right side, we adjust the coefficient of [tex]\( \text{NaCl} \)[/tex] to balance these atoms.

By placing a coefficient of 2 in front of [tex]\( \text{NaCl} \)[/tex]:

[tex]\[ \text{BaCl}_2(\text{aq}) + \text{Na}_2\text{CO}_3(\text{aq}) \rightarrow \text{BaCO}_3(\text{s}) + 2 \text{NaCl}(\text{aq}) \][/tex]

Now, let's recount the atoms on the right side:

- [tex]\( \text{Ba} \)[/tex]: 1
- [tex]\( \text{Cl} \)[/tex]: 2
- [tex]\( \text{Na} \)[/tex]: 2
- [tex]\( \text{C} \)[/tex]: 1
- [tex]\( \text{O} \)[/tex]: 3

4. Verify that both sides are balanced:

- Left side:
- [tex]\( \text{Ba} \)[/tex]: 1
- [tex]\( \text{Cl} \)[/tex]: 2
- [tex]\( \text{Na} \)[/tex]: 2
- [tex]\( \text{C} \)[/tex]: 1
- [tex]\( \text{O} \)[/tex]: 3

- Right side:
- [tex]\( \text{Ba} \)[/tex]: 1
- [tex]\( \text{Cl} \)[/tex]: 2
- [tex]\( \text{Na} \)[/tex]: 2
- [tex]\( \text{C} \)[/tex]: 1
- [tex]\( \text{O} \)[/tex]: 3

Since the counts for all atoms are equal on both sides, the equation is now balanced.

The required coefficient to place in front of [tex]\( \text{NaCl} \)[/tex] to balance the equation is [tex]\( \boxed{2} \)[/tex].
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