Find detailed and accurate answers to your questions on IDNLearn.com. Ask your questions and receive prompt, detailed answers from our experienced and knowledgeable community members.

Select the correct answer.

Which value of [tex]n[/tex] makes this equation true?

[tex] \frac{3n+3}{5} = \frac{5n-1}{9} [/tex]

A. [tex]n = -16[/tex]
B. [tex]n = -2[/tex]
C. [tex]n = 2[/tex]
D. [tex]n = 16[/tex]


Sagot :

To solve the equation [tex]\(\frac{3n + 3}{5} = \frac{5n - 1}{9}\)[/tex], we need to find the value of [tex]\(n\)[/tex] that satisfies this equation. Here's a detailed, step-by-step solution:

1. First, clear the fractions by finding a common denominator.
- The common denominator for 5 and 9 is 45.
- Multiply both sides of the equation by 45 to eliminate the denominators.

[tex]\[ \begin{aligned} 45 \cdot \frac{3n + 3}{5} & = 45 \cdot \frac{5n - 1}{9} \\ 45 \cdot \frac{3n + 3}{5} & = 45 \cdot \frac{5n - 1}{9} \end{aligned} \][/tex]

2. Distribute the 45 to both terms inside each fraction:

[tex]\[ \begin{aligned} 45 \cdot \frac{3n + 3}{5} & = 45 \cdot \frac{5n - 1}{9} \\ \left(\frac{45}{5}\right) \cdot (3n + 3) & = \left(\frac{45}{9}\right) \cdot (5n - 1) \end{aligned} \][/tex]

3. Simplify the coefficients:

[tex]\[ \begin{aligned} 9(3n + 3) & = 5(5n - 1) \\ 27n + 27 & = 25n - 5 \end{aligned} \][/tex]

4. Move all terms involving [tex]\(n\)[/tex] to one side of the equation and constants to the other:

[tex]\[ \begin{aligned} 27n + 27 &= 25n - 5 \\ 27n - 25n &= -5 - 27 \\ 2n &= -32 \end{aligned} \][/tex]

5. Solve for [tex]\(n\)[/tex]:

[tex]\[ \begin{aligned} 2n &= -32 \\ n &= \frac{-32}{2} \\ n &= -16 \end{aligned} \][/tex]

6. Check the potential solutions among the given choices: [tex]\(n = -16\)[/tex], [tex]\(n = -2\)[/tex], [tex]\(n = 2\)[/tex], and [tex]\(n = 16\)[/tex]

- The correct answer is [tex]\(n = -16\)[/tex].

Therefore, the value of [tex]\(n\)[/tex] that makes the equation [tex]\(\frac{3n + 3}{5} = \frac{5n - 1}{9}\)[/tex] true is:

A. [tex]\(n = -16\)[/tex]