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If [tex]$4^{2x+1}=4^5$[/tex], then what is the value of [tex]$x$[/tex]?

Sagot :

To solve the equation [tex]\(4^{2x + 1} = 4^5\)[/tex], we can follow these steps:

1. Identify the Bases:
Both sides of the equation have the same base, which is 4.

2. Equate the Exponents:
Since the bases are the same, the exponents must be equal for the equation to hold true. Therefore, we can set the exponents equal to each other:
[tex]\[ 2x + 1 = 5 \][/tex]

3. Isolate the Variable [tex]\(x\)[/tex]:
Solve for [tex]\(x\)[/tex] by first isolating the term containing [tex]\(x\)[/tex]. Subtract 1 from both sides:
[tex]\[ 2x + 1 - 1 = 5 - 1 \][/tex]
Simplifying this, we get:
[tex]\[ 2x = 4 \][/tex]

4. Solve for [tex]\(x\)[/tex]:
Divide both sides of the equation by 2:
[tex]\[ x = \frac{4}{2} \][/tex]
Simplifying this, we find:
[tex]\[ x = 2 \][/tex]

Therefore, the value of [tex]\(x\)[/tex] is [tex]\(\boxed{2}\)[/tex].
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