Answered

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17.3 g of an unknown metal cools from 42 °C to 23 °C and loses 223.5 J of heat. What is the specific heat of the metal in J/(g °C)?

Sagot :

to know the specific heat of the metal we have to use this formula q=mc\Delta T

where;

(q)=223.5J

m=17.3g

\Delta T=(42°C - 32°C)

=10°C

Rearrenging the formula to solve for (c):

c=q/m\Delta T

c=223.5J/17.3g×10A°C

c=223.5/173

c=1.29J(gA°C)

so, specific heat of the metal is (1.29\text{J/(g°C)})

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