Answered

Explore a diverse range of topics and get expert answers on IDNLearn.com. Get thorough and trustworthy answers to your queries from our extensive network of knowledgeable professionals.

Solve for [tex]\( x \)[/tex]:

[tex]\[ 3x = 6x - 2 \][/tex]



Format the following question or task so that it is easier to read.
Fix any grammar or spelling errors.
Remove phrases that are not part of the question.
Do not remove or change LaTeX formatting.
Do not change or remove [tex] [/tex] tags.
If the question is nonsense, rewrite it so that it makes sense.
-----
[tex]$
2 C_2H_2(g) + 5 O_2(g) \rightarrow 4 CO_2(g) + 2 H_2O(g)
$[/tex]

How many liters of [tex]\(C_2H_2\)[/tex] are required to produce [tex]\(8 \, \text{L}\)[/tex] of [tex]\(CO_2\)[/tex], assuming the reaction is at STP?

The ratios are: [tex]\(\frac{2 \, \text{L} \, C_2H_2}{4 \, \text{L} \, CO_2}\)[/tex] or [tex]\(\frac{4 \, \text{L} \, CO_2}{2 \, \text{L} \, C_2H_2}\)[/tex]

[tex]\[ \text{[?]} \, \text{L} \, C_2H_2 \][/tex]

Sagot :

GinnyAnsweridn
Alright, let's solve this step-by-step:

We have the balanced chemical equation:
[tex]\[ 2 \, \text{C}_2\text{H}_2 (\text{g}) + 5 \, \text{O}_2 (\text{g}) \rightarrow 4 \, \text{CO}_2 (\text{g}) + 2 \, \text{H}_2\text{O} (\text{g}) \][/tex]

We need to determine how many liters of [tex]\(\text{C}_2\text{H}_2\)[/tex] are required to produce 8 liters of [tex]\(\text{CO}_2\)[/tex].

From the balanced equation, we know the volume ratios are as follows:
[tex]\[ 2 \, \text{L} \, \text{C}_2\text{H}_2 \text{ produces } 4 \, \text{L} \, \text{CO}_2 \][/tex]

We can set up the ratio of [tex]\(\text{C}_2\text{H}_2\)[/tex] to [tex]\(\text{CO}_2\)[/tex] from the equation:
[tex]\[ \frac{2 \, \text{L} \, \text{C}_2\text{H}_2}{4 \, \text{L} \, \text{CO}_2} \][/tex]

Let [tex]\( x \)[/tex] be the volume of [tex]\(\text{C}_2\text{H}_2\)[/tex] needed to produce 8 liters of [tex]\(\text{CO}_2\)[/tex]:

[tex]\[ \frac{2 \, \text{L} \, \text{C}_2\text{H}_2}{4 \, \text{L} \, \text{CO}_2} = \frac{x \, \text{L} \, \text{C}_2\text{H}_2}{8 \, \text{L} \, \text{CO}_2} \][/tex]

To solve for [tex]\( x \)[/tex], we can cross-multiply:

[tex]\[ 2 \times 8 = 4 \times x \][/tex]
[tex]\[ 16 = 4x \][/tex]

Now, we divide both sides by 4 to isolate [tex]\( x \)[/tex]:

[tex]\[ x = \frac{16}{4} \][/tex]
[tex]\[ x = 4 \][/tex]

Therefore, the volume of [tex]\(\text{C}_2\text{H}_2\)[/tex] required to produce 8 liters of [tex]\(\text{CO}_2\)[/tex] is [tex]\( 4 \)[/tex] liters.
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for trusting IDNLearn.com. We’re dedicated to providing accurate answers, so visit us again for more solutions.