IDNLearn.com offers expert insights and community wisdom to answer your queries. Join our platform to receive prompt and accurate responses from experienced professionals in various fields.
Sagot :
Sure, let's tackle these ratio problems step by step.
### Part (a)
Given ratios:
- [tex]\(A : B = 3 : 5\)[/tex]
- [tex]\(A : C = 6 : 7\)[/tex]
#### Step 1: Find a common base for [tex]\(A\)[/tex]
1. From [tex]\(A : B = 3 : 5\)[/tex], we can write [tex]\(A = 3k_1\)[/tex] and [tex]\(B = 5k_1\)[/tex].
2. From [tex]\(A : C = 6 : 7\)[/tex], we can write [tex]\(A = 6k_2\)[/tex] and [tex]\(C = 7k_2\)[/tex].
#### Step 2: Equalize the [tex]\(A\)[/tex] terms
To find the least common multiple (LCM) of the coefficients of [tex]\(A\)[/tex] in both ratios:
- The coefficients are 3 and 6.
- The LCM(3, 6) is 6.
#### Step 3: Adjust the terms
Adjust each ratio so that the [tex]\(A\)[/tex] term is the LCM:
1. [tex]\(A = 6\)[/tex]
- From [tex]\(A = 3k_1\)[/tex]: [tex]\(k_1 = 2\)[/tex]. So, [tex]\(B = 5 \times 2 = 10\)[/tex].
- From [tex]\(A = 6k_2\)[/tex]: [tex]\(k_2 = 1\)[/tex]. So, [tex]\(C = 7 \times 1 = 7\)[/tex].
Thus, the ratio [tex]\(A : B : C\)[/tex] is [tex]\(6 : 10 : 7\)[/tex].
### Part (b)
Given ratios:
- [tex]\(B : C = \frac{1}{2} : \frac{1}{6}\)[/tex]
- [tex]\(A : B = \frac{1}{3} : \frac{1}{5}\)[/tex]
#### Step 1: Simplify the ratios
1. Simplify [tex]\(B : C = \frac{1}{2} : \frac{1}{6}\)[/tex]:
- Convert to integers by multiplying by 6 (common denominator): [tex]\(B : C = 3 : 1 \)[/tex].
2. Simplify [tex]\(A : B = \frac{1}{3} : \frac{1}{5}\)[/tex]:
- Convert to integers by multiplying by 15 (common denominator): [tex]\(A : B = 5 : 3\)[/tex].
#### Step 2: Combine the ratios
We have:
- [tex]\(A : B = 5 : 3\)[/tex]
- [tex]\(B : C = 3 : 1\)[/tex]
#### Step 3: Equalize the [tex]\(B\)[/tex] terms
Since [tex]\(B\)[/tex] is already the same in both ratios, we can combine them directly.
1. From [tex]\(A : B\)[/tex], we have [tex]\(A = 5k\)[/tex] and [tex]\(B = 3k\)[/tex].
2. From [tex]\(B : C\)[/tex], we have [tex]\(B = 3m\)[/tex] and [tex]\(C = m\)[/tex].
Set the [tex]\(B\)[/tex] terms equal:
- [tex]\(3k = 3m\)[/tex]
- [tex]\(k = m\)[/tex]
Thus, [tex]\(A = 5k\)[/tex], [tex]\(B = 3k\)[/tex], and [tex]\(C = k\)[/tex].
Therefore, the ratio [tex]\(A : B : C = 5k : 3k : k = 1.2 : 3 : 1\)[/tex].
### Final Ratios:
- Part (a): [tex]\(6 : 10 : 7\)[/tex]
- Part (b): [tex]\(1.2 : 3 : 1\)[/tex]
### Part (a)
Given ratios:
- [tex]\(A : B = 3 : 5\)[/tex]
- [tex]\(A : C = 6 : 7\)[/tex]
#### Step 1: Find a common base for [tex]\(A\)[/tex]
1. From [tex]\(A : B = 3 : 5\)[/tex], we can write [tex]\(A = 3k_1\)[/tex] and [tex]\(B = 5k_1\)[/tex].
2. From [tex]\(A : C = 6 : 7\)[/tex], we can write [tex]\(A = 6k_2\)[/tex] and [tex]\(C = 7k_2\)[/tex].
#### Step 2: Equalize the [tex]\(A\)[/tex] terms
To find the least common multiple (LCM) of the coefficients of [tex]\(A\)[/tex] in both ratios:
- The coefficients are 3 and 6.
- The LCM(3, 6) is 6.
#### Step 3: Adjust the terms
Adjust each ratio so that the [tex]\(A\)[/tex] term is the LCM:
1. [tex]\(A = 6\)[/tex]
- From [tex]\(A = 3k_1\)[/tex]: [tex]\(k_1 = 2\)[/tex]. So, [tex]\(B = 5 \times 2 = 10\)[/tex].
- From [tex]\(A = 6k_2\)[/tex]: [tex]\(k_2 = 1\)[/tex]. So, [tex]\(C = 7 \times 1 = 7\)[/tex].
Thus, the ratio [tex]\(A : B : C\)[/tex] is [tex]\(6 : 10 : 7\)[/tex].
### Part (b)
Given ratios:
- [tex]\(B : C = \frac{1}{2} : \frac{1}{6}\)[/tex]
- [tex]\(A : B = \frac{1}{3} : \frac{1}{5}\)[/tex]
#### Step 1: Simplify the ratios
1. Simplify [tex]\(B : C = \frac{1}{2} : \frac{1}{6}\)[/tex]:
- Convert to integers by multiplying by 6 (common denominator): [tex]\(B : C = 3 : 1 \)[/tex].
2. Simplify [tex]\(A : B = \frac{1}{3} : \frac{1}{5}\)[/tex]:
- Convert to integers by multiplying by 15 (common denominator): [tex]\(A : B = 5 : 3\)[/tex].
#### Step 2: Combine the ratios
We have:
- [tex]\(A : B = 5 : 3\)[/tex]
- [tex]\(B : C = 3 : 1\)[/tex]
#### Step 3: Equalize the [tex]\(B\)[/tex] terms
Since [tex]\(B\)[/tex] is already the same in both ratios, we can combine them directly.
1. From [tex]\(A : B\)[/tex], we have [tex]\(A = 5k\)[/tex] and [tex]\(B = 3k\)[/tex].
2. From [tex]\(B : C\)[/tex], we have [tex]\(B = 3m\)[/tex] and [tex]\(C = m\)[/tex].
Set the [tex]\(B\)[/tex] terms equal:
- [tex]\(3k = 3m\)[/tex]
- [tex]\(k = m\)[/tex]
Thus, [tex]\(A = 5k\)[/tex], [tex]\(B = 3k\)[/tex], and [tex]\(C = k\)[/tex].
Therefore, the ratio [tex]\(A : B : C = 5k : 3k : k = 1.2 : 3 : 1\)[/tex].
### Final Ratios:
- Part (a): [tex]\(6 : 10 : 7\)[/tex]
- Part (b): [tex]\(1.2 : 3 : 1\)[/tex]
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to assisting you again.