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Solve the inequality [tex]-4y + 6 \ \textless \ -14[/tex].

A. [tex]y \leq 5[/tex]
B. [tex]y \ \textgreater \ 2[/tex]
C. [tex]y \ \textless \ 5[/tex]
D. [tex]y \ \textgreater \ 5[/tex]


Sagot :

To solve the inequality [tex]\(-4y + 6 < -14\)[/tex], follow these steps:

1. Subtract 6 from both sides:
[tex]\[ -4y + 6 - 6 < -14 - 6 \][/tex]
Simplifying, we get:
[tex]\[ -4y < -20 \][/tex]

2. Divide both sides by -4:
When you divide both sides of an inequality by a negative number, you need to reverse the inequality sign.
[tex]\[ \frac{-4y}{-4} > \frac{-20}{-4} \][/tex]
Simplifying, we get:
[tex]\[ y > 5 \][/tex]

Therefore, the solution to the inequality [tex]\(-4y + 6 < -14\)[/tex] is:

[tex]\[ \boxed{y > 5} \][/tex]

So, the correct answer is [tex]\(\boxed{D. y > 5}\)[/tex].