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Assume that each tablet's mass was [tex]$1,000 \text{ mg}$[/tex], and you used 0.200 L of water each time. Compute the reaction rate to the nearest whole number using the formula below.

[tex]\[
\text{Reaction Rate} = \frac{\text{mass of tablet} / \text{volume of water}}{\text{reaction time}}
\][/tex]

For the following conditions:

[tex]$3^{\circ} C \quad$[/tex] Reaction time [tex]$=138.5 \text{ sec}$[/tex]
Reaction rate [tex]$=$[/tex] [tex]$\square \text{ mg/L/sec}$[/tex]

[tex]$24^{\circ} C \quad$[/tex] Reaction time [tex]$=34.2 \text{ sec}$[/tex]
Reaction rate [tex]$=$[/tex] [tex]$\square \text{ mg/L/sec}$[/tex]

[tex]$40^{\circ} C \quad$[/tex] Reaction time [tex]$=26.3 \text{ sec}$[/tex]
Reaction rate [tex]$=$[/tex] [tex]$\square \text{ mg/L/sec}$[/tex]

[tex]$65^{\circ} C \quad$[/tex] Reaction time [tex]$=14.2 \text{ sec}$[/tex]
Reaction rate [tex]$=$[/tex] [tex]$\square \text{ mg/L/sec}$[/tex]


Sagot :

To find the reaction rate for each temperature, we use the formula:

[tex]\[ \text{Reaction Rate} = \frac{\text{mass of tablet} / \text{volume of water}}{\text{reaction time}} \][/tex]

Given:

- Mass of tablet = [tex]\(1000 \, \text{mg}\)[/tex]
- Volume of water = [tex]\(0.200 \, \text{L}\)[/tex]

For each temperature, we will plug in the reaction time to find the reaction rate. Let's do this step-by-step:

### 1. At [tex]\(3^{\circ} C\)[/tex]:
- Reaction time = [tex]\(138.5 \, \text{sec}\)[/tex]

[tex]\[ \text{Reaction Rate} = \frac{1000 \, \text{mg} / 0.200 \, \text{L}}{138.5 \, \text{sec}} = \frac{5000 \, \text{mg/L}}{138.5 \, \text{sec}} \][/tex]

Calculating this:

[tex]\[ \text{Reaction Rate} \approx 36 \, \text{mg/L/sec} \][/tex]

### 2. At [tex]\(24^{\circ} C\)[/tex]:
- Reaction time = [tex]\(34.2 \, \text{sec}\)[/tex]

[tex]\[ \text{Reaction Rate} = \frac{1000 \, \text{mg} / 0.200 \, \text{L}}{34.2 \, \text{sec}} = \frac{5000 \, \text{mg/L}}{34.2 \, \text{sec}} \][/tex]

Calculating this:

[tex]\[ \text{Reaction Rate} \approx 146 \, \text{mg/L/sec} \][/tex]

### 3. At [tex]\(40^{\circ} C\)[/tex]:
- Reaction time = [tex]\(26.3 \, \text{sec}\)[/tex]

[tex]\[ \text{Reaction Rate} = \frac{1000 \, \text{mg} / 0.200 \, \text{L}}{26.3 \, \text{sec}} = \frac{5000 \, \text{mg/L}}{26.3 \, \text{sec}} \][/tex]

Calculating this:

[tex]\[ \text{Reaction Rate} \approx 190 \, \text{mg/L/sec} \][/tex]

### 4. At [tex]\(65^{\circ} C\)[/tex]:
- Reaction time = [tex]\(14.2 \, \text{sec}\)[/tex]

[tex]\[ \text{Reaction Rate} = \frac{1000 \, \text{mg} / 0.200 \, \text{L}}{14.2 \, \text{sec}} = \frac{5000 \, \text{mg/L}}{14.2 \, \text{sec}} \][/tex]

Calculating this:

[tex]\[ \text{Reaction Rate} \approx 352 \, \text{mg/L/sec} \][/tex]

So, the reaction rates to the nearest whole number are:

- At [tex]\(3^{\circ} C\)[/tex], the reaction rate = [tex]\(36 \, \text{mg/L/sec}\)[/tex]
- At [tex]\(24^{\circ} C\)[/tex], the reaction rate = [tex]\(146 \, \text{mg/L/sec}\)[/tex]
- At [tex]\(40^{\circ} C\)[/tex], the reaction rate = [tex]\(190 \, \text{mg/L/sec}\)[/tex]
- At [tex]\(65^{\circ} C\)[/tex], the reaction rate = [tex]\(352 \, \text{mg/L/sec}\)[/tex]
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