To determine the value of [tex]\(\log_3 9\)[/tex], we need to find the exponent [tex]\(x\)[/tex] such that [tex]\(3^x = 9\)[/tex].
First, we recognize that 9 can be written as [tex]\(3^2\)[/tex]. Thus, we have:
[tex]\[ 3^x = 3^2 \][/tex]
Since the bases are the same, we can equate the exponents:
[tex]\[ x = 2 \][/tex]
Hence, the value of [tex]\(\log_3 9\)[/tex] is [tex]\(2\)[/tex].
The correct answer is:
B. 2
