Get the answers you need from a community of experts on IDNLearn.com. Our Q&A platform offers detailed and trustworthy answers to ensure you have the information you need.

Two girls have 91 pence between them. If the first has six times as much as the other, how much does the second have?

Sagot :

Certainly! Let's determine how much each girl has step-by-step.

1. Define Variables:
- Let the amount of money the second girl has be [tex]\( x \)[/tex].
- Therefore, the first girl has 6 times as much as the second girl, which is [tex]\( 6x \)[/tex].

2. Set Up the Equation:
- Together, they have a total of 91 pence.
- So, we can set up the equation based on their combined money:
[tex]\[ x + 6x = 91 \][/tex]

3. Combine Like Terms:
- Simplify the equation:
[tex]\[ 7x = 91 \][/tex]

4. Solve for [tex]\( x \)[/tex]:
- To find [tex]\( x \)[/tex], divide both sides of the equation by 7:
[tex]\[ x = \frac{91}{7} \][/tex]
- This gives us:
[tex]\[ x = 13 \][/tex]

Thus, the second girl has 13 pence.

5. Substitute to Find the First Girl's Amount:
- Since the first girl has 6 times as much as the second girl:
[tex]\[ 6x = 6 \times 13 = 78 \][/tex]

So, the first girl has 78 pence.

In conclusion, the second girl has 13 pence.