Join the IDNLearn.com community and start exploring a world of knowledge today. Get step-by-step guidance for all your technical questions from our knowledgeable community members.
Sagot :
Sure, let's solve the problem step by step.
### Given:
- Skewness ([tex]\( g_1 \)[/tex]): 0.5
- Coefficient of Variation (CV): [tex]\( 40\% \)[/tex]
- Mode ([tex]\( M \)[/tex]): 80
First, let's convert the percentage of the coefficient of variation into a decimal form:
[tex]\[ CV = 40\% = 0.4 \][/tex]
The Pearson coefficient of skewness formula for finding the mean ([tex]\( \mu \)[/tex]) using mode ([tex]\( M \)[/tex]) is given by:
[tex]\[ \text{Skewness} = 3 \times \frac{\mu - M}{\sigma} \][/tex]
where [tex]\( \sigma \)[/tex] is the standard deviation.
Additionally, the coefficient of variation (CV) relates the standard deviation and the mean as follows:
[tex]\[ CV = \frac{\sigma}{\mu} \][/tex]
From the given data:
[tex]\[ 0.5 = 3 \times \frac{\mu - 80}{\sigma} \][/tex]
[tex]\[ CV = 0.4 = \frac{\sigma}{\mu} \][/tex]
We need to solve for the mean ([tex]\( \mu \)[/tex]). Let's first express [tex]\(\sigma\)[/tex] from the coefficient of variation formula:
[tex]\[ \sigma = 0.4 \mu \][/tex]
Substituting [tex]\(\sigma = 0.4 \mu\)[/tex] into the skewness equation:
[tex]\[ 0.5 = 3 \times \frac{\mu - 80}{0.4 \mu} \][/tex]
Rewriting this equation:
[tex]\[ 0.5 = 3 \times \frac{\mu - 80}{0.4 \mu} \][/tex]
[tex]\[ 0.5 = \frac{3 (\mu - 80)}{0.4 \mu} \][/tex]
[tex]\[ 0.5 = \frac{7.5 (\mu - 80)}{\mu} \][/tex]
Multiply both sides of the equation by [tex]\(\mu\)[/tex]:
[tex]\[ 0.5 \mu = 7.5 (\mu - 80) \][/tex]
Distribute and simplify:
[tex]\[ 0.5 \mu = 7.5 \mu - 600 \][/tex]
To isolate [tex]\(\mu\)[/tex], combine like terms by moving all terms involving [tex]\(\mu\)[/tex] to one side of the equation:
[tex]\[ 0.5 \mu - 7.5 \mu = -600 \][/tex]
[tex]\[ -7 \mu = -600 \][/tex]
Divide both sides by -7:
[tex]\[ \mu = \frac{600}{7} \][/tex]
[tex]\[ \mu \approx 85.714 \][/tex]
Thus, the mean ([tex]\( \mu \)[/tex]) of the distribution is approximately [tex]\( 85.714 \)[/tex]. The mode ([tex]\( M \)[/tex]) is given as 80.
### Final answer:
- Mean ([tex]\( \mu \)[/tex]): approximately [tex]\( 85.714 \)[/tex]
- Mode ([tex]\( M \)[/tex]): [tex]\( 80 \)[/tex]
These values satisfy the conditions provided in the problem statement.
### Given:
- Skewness ([tex]\( g_1 \)[/tex]): 0.5
- Coefficient of Variation (CV): [tex]\( 40\% \)[/tex]
- Mode ([tex]\( M \)[/tex]): 80
First, let's convert the percentage of the coefficient of variation into a decimal form:
[tex]\[ CV = 40\% = 0.4 \][/tex]
The Pearson coefficient of skewness formula for finding the mean ([tex]\( \mu \)[/tex]) using mode ([tex]\( M \)[/tex]) is given by:
[tex]\[ \text{Skewness} = 3 \times \frac{\mu - M}{\sigma} \][/tex]
where [tex]\( \sigma \)[/tex] is the standard deviation.
Additionally, the coefficient of variation (CV) relates the standard deviation and the mean as follows:
[tex]\[ CV = \frac{\sigma}{\mu} \][/tex]
From the given data:
[tex]\[ 0.5 = 3 \times \frac{\mu - 80}{\sigma} \][/tex]
[tex]\[ CV = 0.4 = \frac{\sigma}{\mu} \][/tex]
We need to solve for the mean ([tex]\( \mu \)[/tex]). Let's first express [tex]\(\sigma\)[/tex] from the coefficient of variation formula:
[tex]\[ \sigma = 0.4 \mu \][/tex]
Substituting [tex]\(\sigma = 0.4 \mu\)[/tex] into the skewness equation:
[tex]\[ 0.5 = 3 \times \frac{\mu - 80}{0.4 \mu} \][/tex]
Rewriting this equation:
[tex]\[ 0.5 = 3 \times \frac{\mu - 80}{0.4 \mu} \][/tex]
[tex]\[ 0.5 = \frac{3 (\mu - 80)}{0.4 \mu} \][/tex]
[tex]\[ 0.5 = \frac{7.5 (\mu - 80)}{\mu} \][/tex]
Multiply both sides of the equation by [tex]\(\mu\)[/tex]:
[tex]\[ 0.5 \mu = 7.5 (\mu - 80) \][/tex]
Distribute and simplify:
[tex]\[ 0.5 \mu = 7.5 \mu - 600 \][/tex]
To isolate [tex]\(\mu\)[/tex], combine like terms by moving all terms involving [tex]\(\mu\)[/tex] to one side of the equation:
[tex]\[ 0.5 \mu - 7.5 \mu = -600 \][/tex]
[tex]\[ -7 \mu = -600 \][/tex]
Divide both sides by -7:
[tex]\[ \mu = \frac{600}{7} \][/tex]
[tex]\[ \mu \approx 85.714 \][/tex]
Thus, the mean ([tex]\( \mu \)[/tex]) of the distribution is approximately [tex]\( 85.714 \)[/tex]. The mode ([tex]\( M \)[/tex]) is given as 80.
### Final answer:
- Mean ([tex]\( \mu \)[/tex]): approximately [tex]\( 85.714 \)[/tex]
- Mode ([tex]\( M \)[/tex]): [tex]\( 80 \)[/tex]
These values satisfy the conditions provided in the problem statement.
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your questions find clarity at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.